{"id":2215,"date":"2023-03-06T21:11:53","date_gmt":"2023-03-06T20:11:53","guid":{"rendered":"https:\/\/mxth.dk\/?p=2215"},"modified":"2026-04-24T00:17:22","modified_gmt":"2026-04-23T22:17:22","slug":"fordoblingstid","status":"publish","type":"post","link":"https:\/\/mxth.dk\/?p=2215","title":{"rendered":"Fordoblingskonstant"},"content":{"rendered":"\n<blockquote class=\"wp-block-quote eplus-wrapper is-layout-flow wp-block-quote-is-layout-flow\" style=\"font-style:normal;font-weight:200\">\n<p class=\" eplus-wrapper\">I would point out is that most of the change over the past 5,000 years has been arithmetic, and it now logarithmic.<\/p>\n\n\n\n<p class=\" eplus-wrapper\">Digitization, the whole Moore&#8217;s law thing where it doubles every 18 months &#8211; that is a speed that is faster than most people are used to.<\/p>\n<cite>Ken Moelis<\/cite><\/blockquote>\n\n\n\n<p class=\" eplus-wrapper\">Vi har nu set p\u00e5 b\u00e5de eksponentiel- og logaritmefunktioner og deres indbyrdes forhold. Vi skal her til sidst se p\u00e5 en egenskab ved eksponentielle funktioner.<\/p>\n\n\n<p class=\" has-tertiary-background-color has-background eplus-wrapper eplus-styles-uid-364efc\">Hvis vi for eksempel har en konto i banken hvor p\u00e5 der pr dags dato st\u00e5r 1000kr og renten er 1,25% kunne vi v\u00e6re interesseret i at vide hvor lang tid der g\u00e5r inden bel\u00f8bet er fordoblet.<\/p>\n\n\n<p class=\" eplus-wrapper\">Vi har tidligere snakket om at for en eksponentiel funktion s\u00e5 vokser den med den samme procent n\u00e5r x-v\u00e6rdien \u00f8ges med \u00e9n underordnet hvor henne p\u00e5 x-aksen vi befinder os. Det er m\u00e5ske derfor heller ikke s\u00e5 m\u00e6rkeligt at x-v\u00e6rdien \u00f8ges med den samme v\u00e6rdi n\u00e5r y-v\u00e6rdien fordobles.&nbsp;<\/p>\n\n\n<div class=\"wp-block-group eplus-wrapper is-layout-constrained wp-block-group-is-layout-constrained eplus-styles-uid-8dccd1\">\n<p class=\" eplus-wrapper\">E. coli er en kendt og nok den mest studerede bakterie i l\u00f8bet af de sidste 60 \u00e5r. I naturen har den en cyklus, hvor den deler sig hver 15. time, hvorfor der hver 15. time er dobbelt s\u00e5 mange bakterier som der fra 15. timer f\u00f8r, med den betingelse at der ikke er nogle af dem der d\u00f8r. At undg\u00e5 celled\u00f8d er mere realistisk at opn\u00e5 i et laboratorie og her vil tiden der g\u00e5r for at en bakteriekoloni er fordoblet typisk v\u00e6re 20 minutter da man her kan s\u00f8rge for at der er optimale v\u00e6kstbetingelser. <a href=\"#footnote-1-2215\" id=\"note-1-2215\" rel=\"footnote\">1<\/a><\/p>\n\n\n<figure class=\" wp-block-video aligncenter eplus-wrapper eplus-styles-uid-fda80e\"><video height=\"240\" style=\"aspect-ratio: 232 \/ 240;\" width=\"232\" autoplay controls loop muted src=\"https:\/\/mxth.dk\/wp-content\/uploads\/2023\/03\/Ecoli_celledeling.mp4\" playsinline><\/video><\/figure>\n\n\n<p class=\" eplus-wrapper\">Videoen viser en falskfarvet time-lapse video fra flourescensmikroskopi af en voksende koloni af <em>E. coli<\/em>-celler. Videoen best\u00e5r af 114 billeder, hvor de f\u00f8rste 40 billeder er taget med 4 minutters interval, og de resterende 74 billeder er taget med 2 minutters interval. Hentet fra <em>Aging and Death in an Organism That Reproduces by Morphologically Symmetric Division<\/em> (Steward et al., 2005) <a href=\"https:\/\/doi.org\/10.1371\/journal.pbio.0030045\">https:\/\/doi.org\/10.1371\/journal.pbio.0030045<\/a>. Videoen er licenseret under <a href=\"https:\/\/creativecommons.org\/licenses\/by-sa\/4.0\/\">CC BY-SA 4.0<\/a> <img decoding=\"async\" style=\"width: 16px;\" src=\"https:\/\/mirrors.creativecommons.org\/presskit\/icons\/cc.svg\" alt=\"\"><img decoding=\"async\" style=\"width: 16px;\" src=\"https:\/\/mirrors.creativecommons.org\/presskit\/icons\/by.svg\" alt=\"\"><img decoding=\"async\" style=\"width: 16px;\" src=\"https:\/\/mirrors.creativecommons.org\/presskit\/icons\/sa.svg\" alt=\"\">.<\/p>\n<\/div>\n\n\n\n\n<p class=\" eplus-wrapper\">Den tid der g\u00e5r f\u00f8r en bakteriekoloni eller bel\u00f8bet p\u00e5 en bankkonto er fordoblet kaldes for fordoblingstiden eller mere generelt fordoblingskonstanten.<br><br>Fordoblingskonstanten, \\(T_2\\), er den v\u00e6rdi der skal ligges til \\(x\\)-v\u00e6rdien for at \\(y\\)-v\u00e6rdien for funktionen \\(f(x)\\) fordobles.<\/p>\n\n\n\n<p class=\" has-text-align-center eplus-wrapper\">\\(b\\cdot a^{x+T_2}=2\\cdot f(x)\\)<\/p>\n\n\n\n<p class=\" eplus-wrapper\">Lad os se p\u00e5 en konkret eksponentiel funktion.&nbsp;<\/p>\n\n\n<figure class=\" wp-block-image aligncenter size-full eplus-wrapper eplus-styles-uid-280c62\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"600\" height=\"338\" src=\"https:\/\/i0.wp.com\/mxth.dk\/wp-content\/uploads\/2023\/03\/ezgif.com-video-to-gif4.gif?resize=600%2C338&#038;ssl=1\" alt=\"\" class=\"wp-image-2235\"><\/figure>\n\n\n<p class=\" eplus-wrapper\">Vi kan herover se at hvis \\(y\\)-v\u00e6rdien for B (bl\u00e5) er dobbelt s\u00e5 stor som \\(y\\)-v\u00e6rdien for A (r\u00f8d) s\u00e5 vil forskellen mellem de to \\(x\\)-v\u00e6rdier v\u00e6re ens.<\/p>\n\n\n<figure class=\" wp-block-image aligncenter size-full eplus-wrapper eplus-styles-uid-280c62\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"600\" height=\"338\" src=\"https:\/\/i0.wp.com\/mxth.dk\/wp-content\/uploads\/2023\/03\/ezgif.com-video-to-gif5.gif?resize=600%2C338&#038;ssl=1\" alt=\"\" class=\"wp-image-2237\"><\/figure>\n\n\n<p class=\" eplus-wrapper\">Hvis vi ser p\u00e5 n\u00e5r A(0,1) og B(5,2) s\u00e5 er forskellen p\u00e5 \\(x\\)-v\u00e6rdierne 5. Hvis Ay er 2 og By er 4 er \u0394x stadig 5 og hvis Ay er 4 og By er 8 s\u00e5 er \u0394x stadig 5. N\u00e5r \\(x\\) vokser med 5 fordobles \\(y\\)-v\u00e6rdien.<\/p>\n\n\n\n<p class=\" eplus-wrapper\">Vi kan beregne fordoblingskonstanten (\\(T_2\\)) ved hj\u00e6lp af&nbsp;<\/p>\n\n\n\n<p class=\" has-text-align-center eplus-wrapper\">\\(T_2 = \\frac{\\ln(2)}{\\ln(a)}\\)<\/p>\n\n\n\n<p class=\" eplus-wrapper\">s\u00e5 l\u00e6nge grundtallet a er st\u00f8rre end 1. Det vil sige, at det er en eksponentielt voksende funktion.<\/p>\n\n\n\n<p class=\" eplus-wrapper\">Lad os se p\u00e5 et par eksempler. Vi starter med at se p\u00e5 at bestemme fordoblingskonstanten.<\/p>\n\n\n<div class=\"wp-block-group has-tertiary-background-color has-background eplus-wrapper is-layout-constrained wp-block-group-is-layout-constrained eplus-styles-uid-280c62\">\n<p class=\" eplus-wrapper\">For en eksponentiel funktion er forskriften \\(f(x)=3\\cdot 5^x\\). Bestem fordoblingskonstanten.<\/p>\n\n\n\n<p class=\" eplus-wrapper\"><strong>L\u00d8SNING<\/strong><\/p>\n\n\n\n<p class=\" eplus-wrapper\">Da vi skal finde fordoblingskonstanten og vi kender forskriften og derfor grundtallet kan vi direkte bruge formlen<\/p>\n\n\n\n<p class=\" has-text-align-center eplus-wrapper\">\\(T_2 = \\frac{\\ln(2)}{\\ln(a)}\\)<\/p>\n\n\n\n<p class=\" eplus-wrapper\">Vi inds\u00e6tter v\u00e6rdierne ind i formlen.<\/p>\n\n\n\n<p class=\" has-text-align-center eplus-wrapper\">\\(T_2 = \\frac{\\ln(2)}{\\ln(5)}=0,4307\\)<\/p>\n\n\n\n<p class=\" eplus-wrapper\">Fordoblingskonstanten er derfor 0,4307.<\/p>\n<\/div>\n\n\n<p class=\" eplus-wrapper\">Men vi kan ogs\u00e5 godt bestemme fremskrivningsfaktoren og den relative tilv\u00e6kst hvis vi kender fordoblinskonstanten<\/p>\n\n\n<div class=\"wp-block-group has-tertiary-background-color has-background eplus-wrapper is-layout-constrained wp-block-group-is-layout-constrained eplus-styles-uid-280c62\">\n<p class=\" eplus-wrapper\">P\u00e5 en konto st\u00e5r der 5837kr. Vi har f\u00e5et at vide at det vil tage 51 terminer f\u00f8r dette bel\u00f8b er fordoblet. Hvad er renten p\u00e5 kontoen?<\/p>\n\n\n\n<p class=\" eplus-wrapper\"><strong>L\u00d8SNING<\/strong><\/p>\n\n\n\n<p class=\" eplus-wrapper\">Da vi her kender fordoblingskonstanten men mangler grundtallet kan vi benytte formlen for fordoblingskonstanten og omskrive den.<\/p>\n\n\n\n<p class=\" has-text-align-center eplus-wrapper\">\\(T_2=\\frac{\\ln(2)}{\\ln(a)}\\)<\/p>\n\n\n\n<p class=\" has-text-align-center eplus-wrapper\">\\(\\ln(a)=\\frac{\\ln(2)}{T_2}\\)<\/p>\n\n\n\n<p class=\" eplus-wrapper\">Da vi gerne vil have isoleret \\(a\\) skal vi opl\u00f8fte begge sidder til en eksponent. Men grundtallet og basen p\u00e5 logaritmen skal passe sammen. Vi har derfor at<\/p>\n\n\n\n<p class=\" has-text-align-center eplus-wrapper\">\\(\\ln(a)=\\frac{\\log_2(2)}{T_2}\\)<\/p>\n\n\n\n<p class=\" has-text-align-center eplus-wrapper\">\\(\\log_2(a)=\\frac{1}{T_2}\\)<\/p>\n\n\n\n<p class=\" has-text-align-center eplus-wrapper\">\\(\\mathrm{e}^{\\ln(a)}=\\mathrm{e}^{\\frac{\\ln(2)}{T_2}}\\)<\/p>\n\n\n\n<p class=\" has-text-align-center eplus-wrapper\">\\(a=\\mathrm{e}^{\\frac{1}{T_2}\\cdot\\ln(2)}=(\\mathrm{e}^{\\ln(2)})^\\frac{1}{T_2}=2^\\frac{1}{T_2}\\)<\/p>\n\n\n\n<p class=\" eplus-wrapper\">Vi kan nu inds\u00e6tte v\u00e6rdien for fordoblingskonstanten og finde grundtallet.<\/p>\n\n\n\n<p class=\" has-text-align-center eplus-wrapper\">\\(a=2^{\\frac{1}{51}}=1,0137\\)<\/p>\n\n\n\n<p class=\" eplus-wrapper\">Grundtallet for den eksponentielle funktion der beskriver bel\u00f8bets udvikling er 1,0137 og en rente p\u00e5<\/p>\n\n\n\n<p class=\" has-text-align-center eplus-wrapper\">\\(r=(1,0137-1)\\cdot 100\\%=1,37\\%\\)<\/p>\n\n\n\n<p class=\" eplus-wrapper\">Renten p\u00e5 kontoen er derfor 1,37%.<\/p>\n<\/div>\n\n\n\n\n<p class=\" eplus-wrapper\"><code><div class=\"h5p-iframe-wrapper\"><iframe id=\"h5p-iframe-9\" class=\"h5p-iframe\" data-content-id=\"9\" style=\"height:1px\" src=\"about:blank\" frameBorder=\"0\" scrolling=\"no\" title=\"Opgaver_fordoblingskonstant\"><\/iframe><\/div><\/code><\/p>\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n<h4 class=\" wp-block-heading eplus-wrapper\" id=\"formler\">Formler<\/h4>\n\n\n\n<p class=\" eplus-wrapper\">Vi har for fordoblingskonstanten at vi kan beregne den ved at benytte<\/p>\n\n\n\n<p class=\" has-text-align-center eplus-wrapper\">\\(T_2=\\frac{\\ln(2)}{\\ln(a)}\\)<\/p>\n\n\n\n<p class=\" eplus-wrapper\">og hvis vi skal beregne fremskrivningsfaktoren ud fra fordoblingskonstanten skal vi benytte<\/p>\n\n\n\n<p class=\" has-text-align-center eplus-wrapper\">\\(a=2^\\frac{1}{T_2}\\)<\/p>\n\n\n\n<h4 class=\" wp-block-heading eplus-wrapper\" id=\"opgaver\">Opgaver<\/h4>\n\n\n\n<style>\n  table, th, td {\n    border: 1px solid black;\n    border-collapse: collapse;\n  }\n<\/style>\n<table width=\"100%\" border=\"1\">\n  <thead>\n    <tr>\n      <th scope=\"col\" width=\"33%\" bgcolor=\"#3CB371\">Gr\u00f8n<\/th>\n      <th scope=\"col\" width=\"33%\" bgcolor=\"#FFA500\">Gul<\/th>\n      <th scope=\"col\" width=\"33%\" bgcolor=\"#DC143C\">R\u00f8d<\/th>\n    <\/tr>\n  <\/thead>\n  <tbody>\n    <tr>\n      <td>\n        <p><a href=\"https:\/\/matematikc-hhx.systime.dk\/?id=166#c1032\" target=\"_blank\" rel=\"noopener noreferrer\">matChhx24 3.6.1<\/a><\/p>\n      <\/td>\n      <td>\n        <p><a href=\"https:\/\/matematikc-hhx.systime.dk\/?id=166#c1037\" target=\"_blank\" rel=\"noopener noreferrer\">matChhx24 3.6.3<\/a><\/p>\n      <\/td>\n      <td>\n        <p><a href=\"https:\/\/matematikc-hhx.systime.dk\/?id=166#c1039\" target=\"_blank\" rel=\"noopener noreferrer\">matChhx24 u3.6.1<\/a><\/p>\n      <\/td>\n    <\/tr>\n    <tr>\n      <td>\n        <p><a href=\"https:\/\/matematikc-hhx.systime.dk\/?id=166#c1036\" target=\"_blank\" rel=\"noopener noreferrer\">matChhx24 3.6.2<\/a><\/p>\n      <\/td>\n      <td>\n        <p><a href=\"https:\/\/matematikc-hhx.systime.dk\/?id=166#c1038\" target=\"_blank\" rel=\"noopener noreferrer\">matChhx24 3.6.4<\/a><\/p>\n      <\/td>\n      <td>\n        <p><a href=\"https:\/\/matematikc-hhx.systime.dk\/?id=166#c1040\" target=\"_blank\" rel=\"noopener noreferrer\">matChhx24 u3.6.2<\/a><\/p>\n      <\/td>\n    <\/tr>\n    <tr>\n      <td>\n        <p><a href=\"https:\/\/matematikc-hhx.systime.dk\/?id=166#c1054\" target=\"_blank\" rel=\"noopener noreferrer\">matChhx24 3.6.6<\/a><\/p>\n      <\/td>\n      <td>\n        <p><a href=\"https:\/\/matematikc-hhx.systime.dk\/?id=166#c4147\" target=\"_blank\" rel=\"noopener noreferrer\">matChhx24 3.6.5<\/a><\/p>\n      <\/td>\n      <td>\n        <p><a href=\"https:\/\/matematikc-hhx.systime.dk\/?id=170#c1104\" target=\"_blank\" rel=\"noopener noreferrer\">matChhx24 3.29<\/a><\/p>\n      <\/td>\n    <\/tr>\n    <tr>\n      <td>\n        <p><a href=\"https:\/\/matematikc-hhx.systime.dk\/?id=166#c1057\" target=\"_blank\" rel=\"noopener noreferrer\">matChhx24 3.6.7<\/a><\/p>\n      <\/td>\n      <td>\n        <p><a href=\"https:\/\/matematikc-hhx.systime.dk\/?id=166#c1065\" target=\"_blank\" rel=\"noopener noreferrer\">matChhx24 3.6.9<\/a><\/p>\n      <\/td>\n      <td>\n        <p><a href=\"\" target=\"_blank\" rel=\"noopener noreferrer\"><\/a><\/p>\n      <\/td>\n    <\/tr>\n    <tr>\n      <td>\n        <p><a href=\"https:\/\/matematikc-hhx.systime.dk\/?id=170#c1110\" target=\"_blank\" rel=\"noopener noreferrer\">matChhx24 3.28<\/a><\/p>\n      <\/td>\n      <td>\n        <p><a href=\"https:\/\/matematikc-hhx.systime.dk\/?id=170#c1103\" target=\"_blank\" rel=\"noopener noreferrer\">matChhx24 3.30<\/a><\/p>\n      <\/td>\n      <td>\n        <p><a href=\"\" target=\"_blank\" rel=\"noopener noreferrer\"><\/a><\/p>\n      <\/td>\n    <\/tr>\n  <\/tbody>\n<\/table>\n\n\n\n\n\n<h4 class=\" wp-block-heading eplus-wrapper\" id=\"beviser\">Bevis<\/h4>\n\n\n\n<p class=\" eplus-wrapper\">Det kan findes et bevis i bogen, men dette bevis tager udgangspunkt i at det er begyndelsev\u00e6rdien som vi fordobler. At funktionen fordobles for hver gang vi ligger fordoblingskonstanten til er en s\u00e6rlig egenskab for eksponentielle funktioner, men dette har vi ikke bevist. Vi kan dog sagtens bevise dette.<\/p>\n\n\n\n<p class=\" eplus-wrapper\">Lad den eksponentielle funktion v\u00e6re givet ved \\(f(x)=b\\cdot\\mathrm{e}^x\\). Vi vil gerne bevise at funktionen har en fordoblingskonstant, \\(T_2\\), som opfylder at<\/p>\n\n\n\n<p class=\" has-text-align-center eplus-wrapper\">\\(f(x+T_2)=2\\cdot f(x)\\)<\/p>\n\n\n\n<p class=\" eplus-wrapper\">for alle \\(x\\in Dm(f)\\). Denne ligning udtrykker netop at n\u00e5r vi l\u00e6gger et tal til \\(x\\) i dette tilf\u00e6lde \\(T_2\\) s\u00e5 fordobles funktionsv\u00e6rdien. Dette er uafh\u00e6ngigt af hvor vi st\u00e5r p\u00e5 grafen og vi v\u00e6lger derfor en vilk\u00e5rlig \\(x\\)-v\u00e6rdi, lad os kalde den for \\(x_0\\). Vi har derfor at<\/p>\n\n\n\n<p class=\" has-text-align-center eplus-wrapper\">\\(f(x_0+T_2)=2\\cdot f(x)\\).<\/p>\n\n\n\n<p class=\" eplus-wrapper\">Hvis vi inds\u00e6tter forskriften for funktionen har vi<\/p>\n\n\n\n<p class=\" has-text-align-center eplus-wrapper\">\\(b\\cdot a^{x_0+T_2}=2\\cdot b\\cdot a^{x_0}\\).<\/p>\n\n\n\n<p class=\" eplus-wrapper\">Da der st\u00e5r \\(b\\) p\u00e5 begge sidder kan dette forkortes ud p\u00e5 begge sider<\/p>\n\n\n\n<p class=\" has-text-align-center eplus-wrapper\">\\(a^{x_0+T_2}=2\\cdot a^{x_0}\\).<\/p>\n\n\n\n<p class=\" eplus-wrapper\">Da potensen p\u00e5 venstresiden er et sum kan vi kan her benytte en potensregneregel, nemlig \\(a^{n+m}=a^n\\cdot a^m\\), til at omskrive til<\/p>\n\n\n\n<p class=\" has-text-align-center eplus-wrapper\">\\(a^{x_0}\\cdot a^{T_2}=2\\cdot a^{x_0}\\).<\/p>\n\n\n\n<p class=\" eplus-wrapper\">Vi har nu at der p\u00e5 begge sider er ganget med \\(a^{x_0}\\) og vi kan derfor forkorte ved at dividere med \\(a^{x_0}\\) p\u00e5 begge sider<\/p>\n\n\n\n<p class=\" has-text-align-center eplus-wrapper\">\\(a^{T_2}=2\\).<\/p>\n\n\n\n<p class=\" eplus-wrapper\">Vi er nu n\u00e6sten i m\u00e5l. Vi skal nu bare have isoleret \\(T_2\\) og til dette skal vi selvf\u00f8lgelig benytte en logaritme. Da vi kan v\u00e6lge den logaritme vi har lyst til s\u00e5 v\u00e6lger vi selvf\u00f8lgelig den naturlige logaritme<\/p>\n\n\n\n<p class=\" has-text-align-center eplus-wrapper\">\\(\\ln(a^{T_2})=\\ln(2)\\)<\/p>\n\n\n\n<p class=\" eplus-wrapper\">og s\u00e5 skal vi naturligvis benytte en logaritmeregneregel, \\(\\ln(a^n)=n\\cdot\\ln(a)\\) til at f\u00e5 potensen ned<\/p>\n\n\n\n<p class=\" has-text-align-center eplus-wrapper\">\\(T_2\\cdot\\ln(a)=\\ln(2)\\)<\/p>\n\n\n\n<p class=\" eplus-wrapper\">S\u00e5 mangler der bare at isolere \\(T_2\\) ved at dividere med \\(\\ln(a)\\) p\u00e5 begge sider<\/p>\n\n\n\n<p class=\" has-text-align-center eplus-wrapper\">\\(T_2=\\dfrac{\\ln(2)}{\\ln(a)}\\).<\/p>\n\n\n\n<p class=\" eplus-wrapper\"> L\u00e6g m\u00e6rke til at vi er kommet frem til den samme formel, men da vi har valgt en vilk\u00e5rlig \\(x\\)-v\u00e6rdi s\u00e5 afh\u00e6nger \\(T_2\\) ikke af hvilket \\(x_0\\) vi har valgt. Det g\u00e6lder derfor at konstanten \\(T_2\\) opfylder <\/p>\n\n\n\n<p class=\" has-text-align-center eplus-wrapper\">\\(f(x+T_2)=2\\cdot f(x)\\quad\\forall\\quad x\\in Dm(f)\\) <\/p>\n\n\n\n<p class=\" eplus-wrapper\">og at den netop kan bestemmes ved<\/p>\n\n\n\n<p class=\" has-text-align-center eplus-wrapper\">\\(T_2=\\dfrac{\\ln(2)}{\\ln(a)}\\).<\/p>\n\n\n\n<p class=\" has-text-align-right eplus-wrapper\">\\(\\blacksquare\\)<\/p>\n<div class=\"footnotes\"><hr \/><ol><li id=\"footnote-1-2215\" class=\"footnote\"><p><em>The distribution of bacterial doubling times in the wild<\/em>. (Gibson et al., 2018) <a href=\"https:\/\/doi.org\/10.1098\/rspb.2018.0789\">https:\/\/doi.org\/10.1098\/rspb.2018.0789<\/a> <a href=\"#note-1-2215\" class=\"footnote-return\">&#8617;<\/a><\/p><\/li><!--\/#footnote-1.footnote--><\/ol><\/div><!--\/#footnotes-->","protected":false},"excerpt":{"rendered":"<p>I would point out is that most of the change over the past 5,000 years has been arithmetic, and it now logarithmic. Digitization, the whole Moore&#8217;s law thing where it doubles every 18 months &#8211; that is a speed that is faster than most people are used to. Ken Moelis Vi har nu set p\u00e5 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"ub_ctt_via":"","editor_plus_copied_stylings":"{}","_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[12,36,3],"tags":[],"class_list":["post-2215","post","type-post","status-publish","format-standard","hentry","category-funktioner","category-logaritmefunktioner","category-matematik"],"featured_image_src":null,"author_info":{"display_name":"Henriksen","author_link":"https:\/\/mxth.dk\/?author=1"},"jetpack_featured_media_url":"","jetpack_sharing_enabled":true,"_links":{"self":[{"href":"https:\/\/mxth.dk\/index.php?rest_route=\/wp\/v2\/posts\/2215","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/mxth.dk\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/mxth.dk\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/mxth.dk\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/mxth.dk\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=2215"}],"version-history":[{"count":67,"href":"https:\/\/mxth.dk\/index.php?rest_route=\/wp\/v2\/posts\/2215\/revisions"}],"predecessor-version":[{"id":4428,"href":"https:\/\/mxth.dk\/index.php?rest_route=\/wp\/v2\/posts\/2215\/revisions\/4428"}],"wp:attachment":[{"href":"https:\/\/mxth.dk\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=2215"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/mxth.dk\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=2215"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/mxth.dk\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=2215"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}